Ask question

Ask question

All categories

3 years ago

12

If a data set has 16 data values the number of values in the upper quartile is

1 answer:

babunello [35]3 years ago

3 0

A set of data has an interquartile range of 20 and a lower quartile range of 6. if the data is symmetrica, what is the value of the median?

Please help and explain the outcome..Thanks so much

You might be interested in

If mark has 3 friends help him paint his garage it will take 60 minutes how long will it take if he has 4 friends help him

olga2289 [7]

Answer:

40 minutes

Step-by-step explanation:

hope this will help :)

4 0

3 years ago

Area of a rectangular field is 2c^3-c^2+6 square units. If the length of the field is c-2 units, what is its width ?

Tema [17]

If you just factor the original polynomial(The area) then you will find that one of the factors is c-2(the length) and the other will be the width.
When I factored it, I got 2c+3 as the width.
:)

6 0

2 years ago

What are the coordinates of the midpoint of the line segment with the endpoints (2,-5) and (8,3)

Papessa [141]

Midpoint Formula: $(\frac{x_2+x_1}{2} ,\frac{y_2+y_1}{2} )$

Plug the coordinates into the midpoint formula and solve as such:

$(\frac{2+8}{2} ,\frac{-5+3}{2} )\\\\(\frac{10}{2} ,\frac{-2}{2} )\\\\(5,-1)$

<u>Your midpoint is (5,-1).</u>

7 0

3 years ago

please help me with this math problem, the question is on the picture that i attached, ill mark brainliest if the answer is corr

dsp73

Answer:

cos z = 35 / 37

Step-by-step explanation:

cos z is the ratio of the adjacent side of a triangle (the side adjacent to angle z to the hypotenuse:

cos z = (adj. side) / (hypotenuse)

Here we have cos z = 35 / 37

7 0

3 years ago

Solve for n: c= 6n−5g /11t

qwelly [4]

Answer: $\frac{11tc+5g}{66t}=n$

Step-by-step explanation:

You have the equation $c=6n-\frac{5g}{11t}$ .

Then, to solve for the variable $n$ from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and $11t$ , the least common denominator is $11t$ )

$c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}$

Multiply $11t$ to both sides:

$(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g$

Add $5g$ to both sides:

$11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt$

And finally divide both sides by $66t$ :

$\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n$

3 0

3 years ago