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3 years ago

Car A is traveling east at a steady speed of 60 miles per hour. After 2 hours, it is 150 miles east of Johnstown.

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

8 0

Answer:

Its D.

Step-by-step explanation:

Just did it.

zhenek [66]3 years ago

3 0

Answer:

Step-by-step explanation:

just did it

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What are the least common multiple of 12,24,16?

vekshin1

Least Common Multiple is :

Calculate Least Common Multiple for :

12, 16 and 24

Factorize of the above numbers :

12 = 22 • 3

16 = 24

24 = 23 • 3

LCM = 24 • 3

Least Common Multiple is :

Please mark brainliest again because someone deleted my answer

8 0

3 years ago

Put the following equation of a line into slope-intercept form, simplifying all

muminat

Answer:

y = 3/4 + 7

Step-by-step explanation:

you must put the equation into the form of y = mx + b

add 6x to both sides and put it in front of the 56

8y = 6x + 56

y must be by itself by x does not so we divide everything by 8

y = 6/8x + 7

we must simplify the fraction 6/8

y = 3/4x + 7

7 0

2 years ago

Can you please help me

Airida [17]

Answer:

Do u need slope?

Step-by-step explanation:

5 0

3 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$

When t = 0, N = 400

$400 = 725 - C e^{-k*0}\\400 = 725 - C\\C = 725 - 400\\C = 325$

When t = 3, N = 650

$650 = 725 - (325 * e^{-3k})\\325 * e^{-3k} = 75\\e^{-3k} = 75/325\\e^{-3k} = 0.23\\-3k = ln 0.23\\-3k = -1.47\\k = 1.47/3\\k = 0.49$

The equation for the population becomes:

$N = 725 - 325 e^{-0.49t}$

At t = 5, the population becomes:

$N = 725 - 325 e^{-0.49*5}\\N = 725 - 325 e^{-2.45}\\N = 696.95\\N(5) = 697$

N(5) = 700 ( to the nearest 50)

6 0

3 years ago

WILL GIVE BRAINIEST!!!!!!

Veseljchak [2.6K]

Answer:

The answer is y = x

Hope this helps!

4 0

3 years ago