Answer:

Step-by-step explanation:
Given

Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:


Since 9 falls in
category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)

Answer: area is 286.16 ft²
Step-by-step explanation:
Length of the sand pit is 29.2 feet and the width is 9.8 feet.
L= 29.2 ft
W = 9.8 ft
To find out the area, all we have to do is multiply the lenght by the width:
And do not forget that to calculate the area, all units must be the same and for the area, it is always the unit squared, in this case, feet square or simply (ft²).
A = l*w
A = 29.2 * 9.8 = 286.16 ft²
Answer:
50
Step-by-step explanation:
The length of the midsegment is half the length of the base segment, so you have ...
... 2(6x +2) = 2x +84
... 10x = 80 . . . . . . . . . simplify, subtract 2x+4
... x = 8
The length of the midsegment is 6·8+2 = 50.
Answer:
The answer is 236 cu. In.
Step-by-step explanation:
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Step-by-step explanation:
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