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forsale [732]
3 years ago
9

Please help me with this question I’m doing points

Mathematics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

the answer is simply 17/24

shepuryov [24]3 years ago
6 0

Answer:

The first option \frac{17}{21}

Step-by-step explanation:

In order to solve this question we have to add the three fractions. In order to add the fraction we need them to have the least common dinoinator. For 3, 7, and 21 it is 21. So...

\frac{2}{3} - \frac{4}{7} + \frac{15}{21} = \frac{14}{21} - \frac{12}{21}  + \frac{15}{21} = \frac{17}{21}

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A rectangle has an area of 12 square feet and a length of 5 feet. What is its width?
Lera25 [3.4K]
Well, you know that the area of the rectangle is 12 square feet. And you know one of the numbers multiplied to get 12 is 5, so divide 12 by 5. You would get 2.4 as the other number needed.
In this case, 5 feet is the width and 2.4 feet is the length.
8 0
3 years ago
Read 2 more answers
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
Please select the word from the list that best fits the definition
Marat540 [252]

Answer:

quadrilateral

Step-by-step explanation:

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i think my my mom figured out i was bi and she is gonna be mad what do i do i think she is gonna whip me HELP ME PLS
Eva8 [605]
If you can you should go to a friends house for a while until you feel like it’s safe to go back
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mrs. West took her class on a field trip to the museum cost of admission for the girls was $90 and the cost of admission for the
timofeeve [1]

Answer:

15 dollars

Step-by-step explanation:

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