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Inessa05 [86]
3 years ago
5

The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit

the ground ?Round to the nearest hundresth of a second?
Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0   Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.


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I think we need to divide some numbers there
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What is the answer to 3-(x-2)+7​
hram777 [196]

Answer:

3x+13

Step-by-step explanation:

-(x-2) =-x+2

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3 years ago
If x+y=12 and xy=15,find the value of (x^2+y^2)
Mice21 [21]

Answer:  x^2+y^2=\dfrac{105\pm 18\sqrt6}{2}

<u>Step-by-step explanation:</u>

EQ1:  x + y = 12     --> x = 12 - y

EQ2:  xy = 15      

Substitute x = 12-y into EQ2 to solve for y:

(12 - y)y = 15

12y - y² = 15

0 = y² - 12y + 15

    ↓     ↓         ↓

  a=1   b= -12   c=15

.\  y=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\.\quad =\dfrac{-(-12)\pm \sqrt{(-12)^2-4(1)(15)}}{2(1)}\\\\\\.\quad =\dfrac{12\pm \sqrt{144-120}}{2}\\\\\\.\quad =\dfrac{12\pm \sqrt{24}}{2}\\\\\\.\quad =\dfrac{12\pm 2\sqrt{6}}{2}\\\\\\.\quad =6\pm \sqrt{6}

Now, let's solve for x:

xy=15\\\\x(6\pm\sqrt6)=15\\\\x=\dfrac{15}{6\pm\sqrt6}\\\\\\x=\dfrac{15}{6\pm\sqrt6}\bigg(\dfrac{6\pm\sqrt6}{6\pm\sqrt6}\bigg)=\dfrac{6\pm \sqrt6}{2}

Lastly, find x² + y² :

y^2=(6\pm \sqrt6)^2\quad \rightarrow \quad y^2=36\pm 12\sqrt6 +6\quad \rightarrow \quad y^2=42\pm 12\sqrt6

x^2=\bigg(\dfrac{6\pm \sqrt6}{2}\bigg)^2\quad \rightarrow \quad x^2=\dfrac{42\pm 12\sqrt6}{4}\quad \rightarrow \quad x^2=\dfrac{21\pm 6\sqrt6}{2}

                                                                                 

x^2+y^2=\dfrac{21\pm 6\sqrt6}{2}+42\pm 12\sqrt6\\\\\\.\qquad \quad = \dfrac{21\pm 6\sqrt6}{2}+\dfrac{84\pm 24\sqrt6}{2}\\\\\\. \qquad \quad = \dfrac{105\pm 18\sqrt6}{2}

5 0
3 years ago
If the perimeter of the regular pentagon is 75 cm what is the length of each side
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Type the correct answer in each box. use numerals instead of words. students in a reading class have three options for their boo
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The answers to the questions on how she would use the colored chips are given here:

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The proof is that 6 + 4 + 10 still gives us 20

Read more on percentages here: brainly.com/question/24877689

#SPJ1

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