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Inessa05 [86]
3 years ago
5

The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit

the ground ?Round to the nearest hundresth of a second?
Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0   Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.


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Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

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(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

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Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

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