Answer:
213 books
Step-by-step explanation:
Paper books = $1.45 each
$ 1.45 = 1 paper book
$ 1 = 1/1.45 paper book
$98.6 = 98.6/1.45 paper books
$ 98.6 = 68 paper books
Hardback books = $ 2.25 each
$2.25 = 1 Hardbook
$1 = 1/2.25 hardbook
$ 328.10 = 328.10/2.25 hardbooks
$ 328.10 = 145.822 hard books
Number of books cannot be a decimal number, so the value has to be estimated to a nearer whole number.
$ 328.10 = 145 hard books
Total number of books bought = (145 + 68)books= 213 books (Answer)
It depends on the number but you can say 345 times 2 and the answer is 690. Hope that helps.
Did you mean -21(-2-5)+(-14)+6(8-4.3) ?
If that, the answer is 155.2:)) im sorry if im wrong:((
Step-by-step explanation:
Given that Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. We are to calculate the probability that Rita will need to pick atleast 5 beads before she picks a grey bead from her collection.
Prob for drawing atleast 5 beads before she picks a grey bead from her collection
= 1-Prob for drawing atleast one grey beed in the first 5 draws.
(Because these two are complementary events)
no of grey beeds drawn in first 5 trials is
Bi=(5,1/6)
Prob for drawing atleast one grey beed in the first 5 draws.
=1-Prob of no grey
Hence required prob=P(X=0 in first 5 draws)
= 0.4018
6th beeds onwards can be grey also.
Nearest answer is c)0.45
Answer:
a
b
c
Step-by-step explanation:
Generally the size of the sample sample space is mathematically represented as
Where N is the total number of objects available and r is the number of objects to be selected
So for a, where N = 19 and r = 8
For b Where N = 25 and r = 3
For c Where N = 23 and r = 2
