Answer:
d)9991.15
Step-by-step explanation:
We have a sum of money ($6000) compounded daily at an annual interest rate of 8.5% for 6 years.
If the interest is compound daily, and we take a m=365 days a year (or 365 subperiods m), the daily nominal interest rate is:
![i_d=\dfrac{i}{m}=\dfrac{0.085}{365}=0.000232877](https://tex.z-dn.net/?f=i_d%3D%5Cdfrac%7Bi%7D%7Bm%7D%3D%5Cdfrac%7B0.085%7D%7B365%7D%3D0.000232877)
Then, we can express the final valueo of $6000 compounded daily at an annual interest rate of 8.5% for 6 years as:
![FV=IV\left(1+\dfrac{i}{m}\right)^{n\cdot m}\\\\\\FV=6000(1+0.000232877)^{6\cdot 365}\\\\FV=6000(1.000232877)^{2190}\\\\FV=6000\cdot1.665192322\\\\FV\approx9991.15](https://tex.z-dn.net/?f=FV%3DIV%5Cleft%281%2B%5Cdfrac%7Bi%7D%7Bm%7D%5Cright%29%5E%7Bn%5Ccdot%20m%7D%5C%5C%5C%5C%5C%5CFV%3D6000%281%2B0.000232877%29%5E%7B6%5Ccdot%20365%7D%5C%5C%5C%5CFV%3D6000%281.000232877%29%5E%7B2190%7D%5C%5C%5C%5CFV%3D6000%5Ccdot1.665192322%5C%5C%5C%5CFV%5Capprox9991.15)
its 54 bro trust me i know what im doing
Answer:
256.51
Step-by-step explanation:
Find the hypotonuese of the trangle (8^2+ 5^2= c^2) then multiply all of them together then multiply by a 1/2.
Have a good day :)
Let the speed of the slower bus be equal to x km/h
let the speed of the faster bus be equal to x+16 km/h
in one hour they are a further 2x+16 km apart
therefore after 5 hours they are 5(2x+16) = 10x + 80 km apart
10x + 80 = 880 km
10x = 800km
x = 80
x + 16 = 96
therefore, the speed of the slower bus is 80 km/h whereas the speed of the second bus is 96 km/h
the answer is D (i think i'm sorry if i get u wrong)