For the fourth term r = 3
Fourth term = 6C3(x)^(6 - 3) (4y)^3 = 20x^3 (64y^3) = 1,280x^3y^3
Answer:no because mixed numbers need atleast a one and a fraction to be mixed number but if there was a fraction then it couldnt equal two because of the 1's
Step-by-step explanation:
I think the answer is (6,-4)
Answer:
y/3. 1/3y
Step-by-step explanation:
1/3y is y/3 because 1*y=y
