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Sauron [17]
4 years ago
15

4. Find the monthly average for each list of year-end utility costs given:

Mathematics
1 answer:
BigorU [14]4 years ago
7 0

Answer:

1486.67 or 1487.

Step-by-step explanation:

Find the average of those three things. Add 2,340 plus 470 plus 1650. You get 4460. Since you have three costs, divided 4460 by 3, which is 1486.6 repeating. Round to the nearest hundredth which is 1486.67. Hope this helps!

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maxwell borrows 1,000 to repair his car at 9% interest if he pays the loan back over the next 1.5 years how much does he pay bac
worty [1.4K]

is interest per 1 year? if so:

interest per year=9%×1000

=90

interest for .5 years=90÷2

=45

1000+90+45=1135

Ans: 1135

6 0
3 years ago
Read 2 more answers
A train averages a speed of 90 miles per hour across the plains and 37.5 miles per hour through the mountains. If a trip of 300
densk [106]
Let p and m represent the numbers of miles in the plains and mountains, respectively.
.. p + m = 300 . . . . . . . the whole trip was 300 miles

time = distance/speed, so the trip time can be written as
.. p/90 + m/37.5 = 3 48/60
.. 5p + 12m = 1710 . . . . . . . . . . multiply by 450 to put in standard form

You can solve these two equations by any of several means. The variable p can be eliminated by subtracting 5 times the first from the second.
.. (5p +12m) -5(p +m) = 1710 -5*300
.. 7m = 210
.. m = 30

30 miles of the trip was through the mountains.
5 0
4 years ago
Read 2 more answers
Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha
kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable X follows a Poisson distributionP(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda

Evaluate the formula at k=2,3:

P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}

#since

4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda

The mean and variance of the Poisson distributed random variable is equal to \lambda:

\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75

#By property variance:

\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125

The expectation is 1.3125

4 0
4 years ago
X+2y=3 <br> 3y+5y=7 <br> I dont know
Lena [83]

Answer:

Step-by-step explanation:

3y+5y=8y

8y=7(divide 8 in both sides to get y)

y=7/8

x+2y=3...but we already know the value of y, so substitute 7/8 to y

x+2(7/8)=3

x+14/8=3

x=3-14/8

=1.25

8 0
3 years ago
if the formula for the perimeter of a rectangle is p=2l+2w, what is the formula for w in terms of p and l
aleksklad [387]

Answer:

(p-2l)/2 = w

Step-by-step explanation:

p=2l+2w


We want to solve for w.

The first step is to subtract 2l from each side

p-2l=2l-2l+2w

p-2l=2w

Then we will divide each side by 2 to isolate w

(p-2l)/2 = 2w/2

(p-2l)/2 = w

3 0
4 years ago
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