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2 years ago

Https://www.linkedin.com/pulse/100-reasons-why-you-shouldnt-commit-sui cide-aaditya-thapa

Mathematics

2 answers:

Gekata [30.6K]2 years ago

4 0

Answer:

9+10=21

bettttt

ima do it anyway

Pepsi [2]2 years ago

3 0

Answer:

thnx for that .............

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PLEASE HELP ME PLEASE!!

Harman [31]

Answer:

hypotenuse (h)=?

perpendicular (p)=3

base(b)=2

using pythagoras theorem

h²=p²+b²

h²=3²+2²

h²=9+4

h²=13

h=√13

hypotenuse (h)=12
perpendicular (p)=10
base(b)=?

using pythagoras theorem

b²=h²-p²

b²=12²-10²

b²=144-100

b=√44

b=2√11

6 0

2 years ago

URGENT NEED HELP FAST

Viefleur [7K]

Answer: I think it’s the 4th one

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Ginny has two vegetable gardens.In the second garden,Ginny grows tomatoes every 3 years.This year,Ginny grows tomatoes in both g

kherson [118]

So it would be in six years because if you do it, it would be
garden 1: 2,4,6,8
garden 2: 3,6,9
and the lowest common multiple is 6 so in 6 years is when it will happen again

7 0

3 years ago

An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin How many pounds of the second alloy

NemiM [27]

Answer:

30 pounds

Step-by-step explanation:

Amount of tin in first alloy + amount of tin in second alloy = amount of tin in mixture

0.15 (20) + 0.10 x = 0.12 (20 + x)

3 + 0.10 x = 2.4 + 0.12 x

0.6 = 0.02 x

x = 30

8 0

3 years ago

Pete, a professional bowler, is unhappy with any game below 200. Over time, 80% of his games exceed this score. What is the prob

Aneli [31]

The probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

It has a range of 0 to 1.

It is given that

Pete, a professional bowler, is unhappy with any game below 200

80% of his games exceed this score.

the probability that Pete exceeds 200 in at least 9 of his next 10 games is given by

P( 9/10 > 200) +P(10/10>200)

The binomial experiment consists of n trial out of it x is success.

$P( x) = \dfrac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$

Here p = 0.8

For 9/10 matches

$P( 9/10 > 200) = \dfrac{10!}{9!(10-9)!}0.8^9(1-0.8)^{10-9}\\\\ = {10}(0.8)^9(0.2)\\= 0.268$

For (10/10 >200)

$P( 10/10 > 200) = \dfrac{10!}{10!(10-10)!}0.8^{10} (1-0.8)^{10-10}\\\\ = {1!}(0.8)^{10}\\= 0.1074$

Therefore the probability that Pete exceeds 200 in at least 9 of his next 10 games is 0.268+0.1074 = 0.3754.

To know more about Probability

brainly.com/question/11234923

#SPJ1

5 0

2 years ago