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3 years ago

Why do vertices connected by a diagonal of a polygon have to be nonconsecutive?

Mathematics

2 answers:

Sever21 [200]3 years ago

8 0

Because consecutive vertices are already connected by the edges of the polygon.

oksian1 [2.3K]3 years ago

8 0

Answer:

Basically, a segment which connects two consecutive vertices is not a diagonal, it's actually a side of a polygon.

So, in order to get a diagonal, you need to unit two nonconsecutive vertices, that way you won't get a side but a diagonal.

Actually, a diagonal of a polygon is defined as a segment which connects two nonconsecutive vertices.

Therefore, by definition, a diagonal must connect two nonconsecutive vertices.

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3 years ago

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3 years ago

Read 2 more answers

The area of the following equilateral triangle is 62.4 square feet that is he height

Vikentia [17]

The height of this triangle would be 10.4

In order to find this, you first must find the length of the sides. Using a manipulated formula for area of an equilateral triangle, we can determine the lengths of the side. Below if the formula.

S = $\frac{2}{3}3^{\frac{3}{4}} \sqrt{A}$

In this, S is the length of the side and A is the area. So we plug in and get:

S = $\frac{2}{3}3^{\frac{3}{4}} \sqrt{62.4}$

S = $\frac{2}{3}3^{\frac{3}{4}} 7.89$

S = 12

Now that we have the side as 12, we can use the Pythagorean Theorem to find the height. If you split a equilateral triangle down the middle, you are left with two right triangles. Using this right triangle, the hypotenuse would be 12, the first leg would be 6 (half of the base) and the height would be the other leg. So we plug in and solve.

$a^{2} + b^{2} = c^{2}$