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Firlakuza [10]
3 years ago
5

Given the following class code: public class RecurseSample { public static void main(String[] args) { System.out.println(recurse

(3)); } public static int recurse(int n) { int total = 0; if (n == 0) { return 0; } else { total = 3 + recurse(n - 1); } return total; } } What values will be printed when this code is executed?
Computers and Technology
1 answer:
Kipish [7]3 years ago
4 0

Answer:

The output of the given code is "9".

Explanation:

In this question, a class "RecurseSample" inside the class a "recurse" method is declared that holds that holds an integer variable as the parameter, and inside the method a total variable is declared and uses a conditional statement to check the n variable value that is equal to 0 if it is true it will return 0. In the else block it call the method and add value in the total variable, and returns its value. In the main method, the print method is used that prints the above method values.

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5 0
2 years ago
Hi, please help me, solution.​
loris [4]

Answer:

error: incompatible types

Explanation:

Given

The attached code

Required

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3 years ago
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3 years ago
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dalvyx [7]

Answer:

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2 years ago
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