1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shkiper50 [21]
3 years ago
7

Бx + 4y= 18 —бх+ бу = -18​

Mathematics
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

x= 3

y = 0

Step-by-step explanation:

•Add the two equations to cancel out +6x and -6x

•Find the value of y

•Substitute the value of y into equation 1 to find the value of x.

Hope I was able to help you:)

You might be interested in
A line that includes the points (4,10) and (7,3) what is the equation in point slope form
stellarik [79]
M = y2-y1/x2-x1
M = 3-10/7-4
M = -7/3
6 0
3 years ago
Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
3 years ago
A function and its inverse are shown on the same graph. Which statement describes the relationship between the function and its
Korvikt [17]

Answer:C

Step-by-step explanation:on edge

5 0
3 years ago
Evaluate the equation.
Tomtit [17]

Answer:

C

Step-by-step explanation:

193b=212.3

193b/193=212.3/193

(divide by 193 to get the value of b)

193 cancels 193

b= 1.098445596

(round off to one decimal place)

b=1.1

Hope its helps ❤️

3 0
2 years ago
Read 2 more answers
On the first play, a football team lost 6 yards, on the second play they gained 20 yards, what was their total change in yards?
Arada [10]
20 - 6 = 14
so the answer is 14
3 0
3 years ago
Other questions:
  • Round 23.84 to 1 decimal point
    6·1 answer
  • Find the value of x.
    8·2 answers
  • What is<br> 2x+y=11<br> 5x+3y=29
    14·2 answers
  • How many times larger is (5.4x10e6)x(9x10e3)
    8·1 answer
  • What’s the missing angle
    7·2 answers
  • I need help for tha pre-test?​
    15·1 answer
  • What is the area of the composite figure? <br> A) 27 <br> B) 21 <br> C) 15<br> D) 30
    11·2 answers
  • 7(m+5) = 21 <br><br>What is it?​
    14·2 answers
  • Examine the steps used to solve the equation.
    9·2 answers
  • A number that is multiplied by another number
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!