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Vlada [557]
3 years ago
5

Please answer this. i’ve asked 3 questions of this same thing bc people don’t even answer them, i’ll give brainliest to whoever

answers correctly. i’m failing and really need this answered
1. A wave has a wavelength of 5 m and a frequency of 2 Hz. At what speed/velocity does the
wave travel?

2. The speed/velocity of a wave on a guitar string is 100m/s and the frequency is 1,000 Hz. What
is the wavelength of the wave?

3. If the speed/velocity of a wave is 25 m/s and the wavelength is 5 m, what is the frequency of
this wave?
Mathematics
1 answer:
Stels [109]3 years ago
7 0

We will be using the formula: Speed = Wavelength * Frequency

1. <u>Given:</u>  Wavelength = 5 m     and     Frequency = 2 Hz

Speed of the wave = Wavelength * Frequency

Speed of the wave = 5 * 2

Speed of the wave = 10 m/s

__________________________________________________________

2. <u>Given:</u> Speed of the wave = 100 m/s   and    Frequency= 1000 Hz

Wavelength = Speed / Frequency

Wavelength = 100 / 1000

Wavelength = 0.1 m

__________________________________________________________

3. <u>Given:</u> Speed of the Wave = 25 m/s           Wavelength = 5 m

Frequency = Speed / Wavelength

Frequency = 25 / 5

Frequency = 5 Hz

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kvv77 [185]

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Hope it helps

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3 years ago
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Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

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2 years ago
What is the greatest common factor of 180 and 240
maria [59]
The GCF of 180 and 240 is 60
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3 years ago
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