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2 years ago

2x-y<-3

Mathematics

1 answer:

timama [110]2 years ago

5 0

Answer:

y > 2x + 3

Step-by-step explanation:

Okay, first let's simplify the equation by understanding the form.

y = mx + b is the form.

Currently we have 2x - y < -3, So we can subtract 2x on both sides to get

-y < -2x - 3

Let's multiply each term by -1 to get

y < 2x + 3, but wait! We have to flip the sign!

The answer is :

y > 2x + 3

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Ivahew [28]

The slope for is JK 1/3 , the slope of LK is -2 , the slope of ML is 2/5 , and the slope of MJ is 3/2 . Quadrilateral JKLM is not a parallelogram because neither pair of opposite sides is parallel

Further explanation:

Given vertices are:

J(−4, 1) , K(2, 3) , L(5, -3) , and M(0, −5) .

We have to find the slopes before concluding any result

The formula for slope is:

$m=\frac{y_2-y_1}{x_2-x_1}$

So:

Slope of JK:

$m_1=\frac{3-1}{2-(-4)}\\=\frac{2}{2+4}\\=\frac{2}{6}\\=\frac{1}{3}$

Slope of LK:

$m_2=\frac{-3-3}{5-2}\\=\frac{-6}{3}\\=-2$

Slope of ML:

$m_3=\frac{-3-(-5)}{5-0}\\=\frac{-3+5}{5}\\=\frac{2}{5}$

Slope of MJ:

$m_4=\frac{1-(-5)}{-4-0}\\=\frac{1+5}{-4}\\=\frac{6}{-4}\\=-\frac{3}{2}$

As the slopes of all sides are different, the given quadrilateral is not a parallelogram because in order for the quadrilateral to be a parallelogram the opposite sides have to be parallel i.e. have equal slopes and there are no sides with equal slopes.

Keywords: Parallelogram, Quadrilateral

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USPshnik [31]

Answer:

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Step-by-step explanation:

$5 {x}^{2} - 40x + 80 \\ =5( {x}^{2} - 8x + 16) \\ = 5 ( {x}^{2} - 8x + {4}^{2} ) \\ = 5 {(x - 4)}^{2}$

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Hey there!

So, if $y=(4)$ , this would mean that we would do $(2 \ * \ 4)$ and from this, we would get 8.

We will then need to find what is $(x)$ .

$(x) = 7$

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So, the equation would really look like . . .

$\left[\begin{array}{ccc} 8*(7)-2*4 = 48 \\ \\ x=\boxed{7}\end{array}\right]$

Hope this helps.
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