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2 years ago

14

Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of si

n x° and cos y° share?

1 answer:

siniylev [52]2 years ago

6 0

Answer:

sin(x)=cos(y)

Step-by-step explanation:

Sin x is 3/hypotenuse and cos(y) is 3/hypotenuse

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a six sided die is rolled 15 times with these results (1,1) (2,3) (3,4) (4,4) (5,1) (6,2) what is the experimental probabilitly

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Answer:

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2 years ago

Skip count 99 Times by tens. there are 9 ones. the number is what.

Alenkasestr [34]

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2 years ago

The average weight of 5 linemen is 215 pounds. The average weight of the 6 skill players is 187 pounds. What is the average weig

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Step-by-step explanation:

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2 years ago

Solve for x write the exact answer using either base -10 or base-e logarithms

jeka57 [31]

<u>Given</u>:

The given expression is $2^{x+5}=13^{2 x}$

We need to determine the value of x using either base - 10 or base - e logarithms.

<u>Value of x:</u>

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if $f(x)=g(x)$ then $\ln (f(x))=\ln (g(x))$

Thus, we get;

$\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)$

Applying the log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ , we get;

$(x+5) \ln (2)=2 x \ln (13)$

Expanding, we get;

$x \ln (2)+5 \ln (2)=2 x \ln (13)$

Subtracting both sides by $5 \ln (2)$ , we get;

$x \ln (2)=2 x \ln (13)-5 \ln (2)$

Subtracting both sides by $2 x \ln (13)$ , we get;

$x \ln (2)-2 x \ln (13)=-5 \ln (2)$

Taking out the common term x, we have;

$x( \ln (2)-2 \ln (13))=-5 \ln (2)$

$x=\frac{-5 \ln (2)}{\ln (2)-2 \ln (13)}$

$x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

Thus, the value of x is $x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

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3 years ago

The value of x is:

Alex Ar [27]

Answer:

No solution

Step-by-step explanation:

Kindly include the figure from which to refer angle x

8 0

3 years ago