Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
2.2to 4 pages in a minute because 12 divided by 3 is 4 and 12 divided by 5 is 2.2
A = π r^2
A = 9^2 <span>π
</span>A = 81<span>π
if using </span>π = 3.14 then
A = 3.14 x 81 = 254.47 ft^2
answer: 81π ft^2 or 254.47 ft^2
hope that helps
Answer:
y=-1/2x+17
Step-by-step explanation:
y=-1/2x+17
Answer:
Insufficient Data
Step-by-step explanation:
Please correct the problem. Given details are not enough or/and precise to suggest solution
