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larisa [96]
3 years ago
6

Plss help i’ll give brainliest thank you!

Mathematics
2 answers:
jeyben [28]3 years ago
8 0

Answer:

D

Step-by-step explanation:

A is wrong because the values are equal.

B is wrong because 5 is greater than 2

C is wrong because 1 is less than 2.

SSSSS [86.1K]3 years ago
3 0

Answer:

D

Step-by-step explanation:

absolute value of -25 is 25

and 25>24

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EastWind [94]

Answer:

Step-by-step explanation:

Before we differentiate, let us assign a variable to the function. Let y be equal to the function i.e let y = 3√x -2/x²

In differentiation if y = ax^{n}, then \frac{dy}{dx} = nax^{n-1} where n is a constant and dy/dx means we are differentiating the function y with respect to x.

Applying the formula o the question given;

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On differentiating the resulting function;

\frac{dy}{dx} = \frac{1}{2}*3x^{\frac{1}{2}-1 }   - (-2)x^{-2-1} \\\\\frac{dy}{dx} = \frac{1}{2}*3x^{-\frac{1}{2}} + 2x^{-3}\\ \\\frac{dy}{dx} = \frac{1}{2}*{\frac{3}{x^{\frac{1}{2} } }} + \frac{2}{x^{3} } \\\\\frac{dy}{dx} = {\frac{3}{2x^{\frac{1}{2} } }} + \frac{2}{x^{3} }\\\\\frac{dy}{dx} = {\frac{3}{2\sqrt{x}  }} + \frac{2}{x^{3} }

To combine the terms, we will add up by finding their LCM.

\frac{dy}{dx} = {\frac{3}{2\sqrt{x}  }} + \frac{2}{x^{3} }\\\frac{dy}{dx}  = \frac{3x^3+4\sqrt{x} }{2x^{3} \sqrt{x}}

3 0
4 years ago
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4 0
4 years ago
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How do I do this I don’t know where to start
seropon [69]
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x²=9409-5184
x= √4225
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the answer is 65m
8 0
3 years ago
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Find the value of x. Round to the nearest degree.<br> 13<br> *<br> 20<br> Not drawn to scale<br> to
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Answer:

Hence option C is correct...hope this helps you:)

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