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3 years ago

Find the slope It can be a proper fraction improper fraction or an integer

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

Answer:

The slope would be 2.5

Step-by-step explanation:

Rise over run, pick 2 points 50/20= 2.5

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The solution for a system of two linear equations is (0, 0). Which equation below could be one of the equations in the system? A

earnstyle [38]

Answer:

y = -3x

Step-by-step explanation:

For the equation to be a part of a system, the point (0,0) must be a part of the line. Since y = -3x is proportional meaning b = 0, its y-intercept is (0,0). This means it must cross through and include (0,0). This is a part of the system.

4 0

3 years ago

Help me with this please!!

Mamont248 [21]

Answer: (2,7)

Midpoint formula = ( $\frac{x1,x2}{2}$ , $\frac{y1,y2}{2}$ )

1 + 3 / 2 = 2

5 + 9 / 2 = 7

7 0

3 years ago

-9 - (-4) = <br> What does that equal to?

CaHeK987 [17]

Answer:

-5

Step-by-step explanation:

When you subtract a negative you end up adding it instead

5 0

3 years ago

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-

Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

$ax^2+bx+c=0$

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}$

In this case, the exercise gives you this Quadratic equation:

$5x^2 + 3x - 4 = 0$

You can identify that the numerical coefficients are:

$a=5\\\\b=3\\\\c= - 4$

Therefore, you can substitute values into the Quadratic formula shown above:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}$

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0

3 years ago

Read 2 more answers

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

4 years ago