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Alex
2 years ago
15

Please help with this question

Mathematics
1 answer:
vredina [299]2 years ago
5 0
165 - 57 and divide that by 2. So that would be 54
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chase and sara went to the candy store. chase bought 5 pieces of fudge and 3 pieces of gum for 5.70. sara bought 2 pieces of fud
Vilka [71]
Let, the cost of 1 piece of fudge = x
Cost of a gum = y

System of equations: 5x + 3y = 5.70
2x + 10y = 3.60

Multiply 1st equation by 2, and second by 5, 
New equations: 10x + 6y = 11.40
10x + 50y = 18

Now, subtract 1st from 2nd, 
44y = 6.60
y = 6.60 / 44
y = 0.15

Substitute it in second equation, 
2x + 10(0.15) = 3.60
2x = 3.60 - 1.5
x = 2.10 / 2
x = 1.05

In short, Cost of a Fudge = $1.05 & Cost of a gum = $0.15

Hope this helps!
6 0
3 years ago
Hey guys! Sorry to bother but I need help with these. 5th grade math, will give brainliest! (If you see multiple questions by me
Delicious77 [7]

Answer:

1/36 and 1/28

Step-by-step explanation:

i believe this is the answer as you should divide the denomonator by the answer as you cannot divide the numerator.

6 0
2 years ago
Please help! This is for Algebra 1
kow [346]
The first answer
-40y3/x5
8 0
3 years ago
Find all real solutions of the equation by completing the square. (Enter your answers as a comma-separated list.) x2 − 4x − 8 =
Nat2105 [25]

Answer:

After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46

Step-by-step explanation:

We need to complete the square:

x^2 − 4x − 8 = 0

x^2 -2(x)(2)+(2)^2 -8 -4 =0

(x^2 -4x +4) - 12 = 0

(x-2)^2 -12 =0

Now, finding the value of x

(x-2)^2 -12 =0

(x-2)^2 = 12

taking square root on both sides

\sqrt{(x-2)^2}= \sqrt{12} \\(x-2) = \pm\sqrt{12} \\x = \pm\sqrt{12} +2\\x = \sqrt{12}+2 \,\,and\,\,x=-\sqrt{12}+2\\x= 3.46+2 \,\,and\,\,x=-3.46+2\\x =5.46\,\,and\,\,x=-1.46

So, After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46

5 0
3 years ago
Is this a function ?
Goshia [24]
I don’t think so, a graph is a function only if the vertical line passes through the graph at one distinct point.

But I’m not exactly sure cus I’m still learning geogebra
6 0
2 years ago
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