Question

find the equation of a circle concentric with the circle x^2+y^2-2x-10y+1=0 passing through the point (2,-3)​

Answer 1

Answer:

Step-by-step explanation:

x²+y²-2x-10y+1=0

compare with x²+y²+2gx+2fy+c=0

center is (-g,-f)

radius=√(g²+f²-c)

2g=-2

g=-1

2f=-10

f=-5

radius=(1,5)

c=1

let eq. of circle be x²+y²-2x-10y+c=0

∵ it passes through (2,-3)

2²+(-3)²-2(2)-10(-3)+c=0

4+9-4+30+c=0

c=-39

eq. of circle is is x²+y²-2x-10y-39=0