The practical domain of time is t ∈ [0, 4.25s].
- The set of values that make feel in a particular context is referred to as the sensible area.
- All feasible solutions are addressed by way of theoretical domains and stages.
- domain names and stages restrict the solution sets such that they may be realistic in the parameters given
- .The ball begins its motion at time t = 0s.
- To locate the time while the ball hits the floor,
- we solve the equation:
- h(t) = -16t² + 68t
- h(t) = 0
- -16t² + 68t = 0
- t(-16t + 68) = 0
- t = 0 and -16t + 68 = 0.
- 16t = 68
- t = 68/16
- t = 4.25
- h(t) is non-negative within the interval [0, 4.25].
- Hence, the practical domain is 0 ≤ t ≤ 4.25 s.
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To find the ratio, you just need to divide the two function and solve it. The calculation would be:
<span>F(t)=Q0(1+r)^t
F(0.11)/F(0.01) = 1.09/1.06
</span>Q0(1+r)^0.11 / Q0(1+r)^0.01 = 1.0291
(1+r)^(0.11-0.01) = <span>1.0291</span>
(1+r)^0.10 = 1.0291
(1+r)^0.10*10 = 1.0283 ^10
(1+r )= 1.3325
r = 0.323
Answer:
The true statements are A and D
Step-by-step explanation:
4 (3(3) + 4) is 52, while 16(3) + 12 is 60
that would not be equivalent in w = 3 but it would in w = 1
Answer:
(0,-2)
Step-by-step explanation:
one way to solve...
3x - y = 2 --> *4
-2x + 4y = -8
multiply the first equation by 4
12x - 4y = 8
-2x + 4y = -8
-----------------
10x = 0
x = 0
y = -2
this method is called elimination
another way to solve...
3x - y = 2 simplify for y to get y = 3x - 2
-2x + 4y = -8 substitute y into this equation to solve for x
-2x + 4(3x - 2) = -8
-2x + 12x - 8 = -8
10x = 0
x = 0
y = -2
substitution
alsoo if there are options, just plug in the numbers to the correct variables
The answer will be c. 130%
and you just got to multiply 1560 times 130 and it give you 12
the you multiply that number for 100 and you will get the answer
