Please help i need the answer for this question asap THANK YOU
1 answer:
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Work shown above! Answer is A = (πD^2)/4. d = diameter
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Answer:
Step-by-step explanation:
STEP 1:
2/3 + 7/10 = ?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(2/3, 7/10) = 30
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
*
+
= ?
Complete the multiplication and the equation becomes
The two fractions now have like denominators so you can add the numerators.
Then:
This fraction cannot be reduced.
The fraction 41/30
is the same as
41 divided by 30
Convert to a mixed number using
long division for 41 ÷ 30 = 1R11, so
41/30 = 1 11/30
Therefore:
2/3+7/10= 1 11/30
STEP 2:
41/30 + -2/3
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(41/30, -2/3) = 30
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
The two fractions now have like denominators so you can add the numerators.
Then:
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using
GCF(21,30) = 3
Therefore:
|
]Eigenvectors are found by the equation 
implying that 
. We then can write:
![A-\lambda I = \left [ \begin{array}{cc} 4-\lambda & 2 \\ 5 & 1-\lambda \end{array}\right ]](https://tex.z-dn.net/?f=%20A-%5Clambda%20I%20%3D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bcc%7D%204-%5Clambda%20%26%202%20%5C%5C%205%20%26%201-%5Clambda%20%5Cend%7Barray%7D%5Cright%20%5D%20)
And:
Gives us the characteristic polynomial:
So, solving for each eigenvector subspace:
![\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]](https://tex.z-dn.net/?f=%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bcc%7D%204%20%26%202%20%5C%5C%205%20%26%201%20%5Cend%7Barray%7D%20%5Cright%20%5D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bc%7D%20x%20%5C%5C%20y%20%5Cend%7Barray%7D%20%5Cright%20%5D%20%3D%20%5Cleft%20%5B%20%5Cbegin%7Barray%7D%7Bc%7D%20-x%20%5C%5C%20-y%20%5Cend%7Barray%7D%20%5Cright%20%5D%20)
Gives us the system of equations:
Producing the subspace along the line
We can see then that 3 is the answer.
And:
Gives us the characteristic polynomial:
So, solving for each eigenvector subspace:
Gives us the system of equations:
Producing the subspace along the line
We can see then that 3 is the answer.