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Papessa [141]
2 years ago
13

Which values of k are solutions to the inequality StartAbsoluteValue negative k minus 2 EndAbsoluteValue less-than 18? Check all

that apply.

Mathematics
2 answers:
Stella [2.4K]2 years ago
6 0

Answer:

You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:

First, remember how the absolute value works:

IxI = x if x ≥ 0

IxI = -x if x ≤ 0

Then if we have something like:

IxI < B

We can rewrite this as

-B < x < B

Now let's answer the question, here we have the inequality:

I-k -2I < 18

Then we can rewrite this as:

-18 < (-k - 2) < 18

Now let's isolate k:

first, we can add 2 in the 3 parts of the inequality:

-18 + 2 < -k - 2 + 2 < 18 + 2

-16 < -k < 20

Now we can multiply all sides by -1, remember that this also changes the direction of the signs, then:

-1*-16 > -1*-k > -1*20

16 > k > -20

Then k can be any value between these two limits.

So the correct options (from the given ones) are:

k = -16

k = -8

k = 0

ddd [48]2 years ago
4 0

Answer:

C, D, E

Step-by-step explanation:

Edge 2021

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3 years ago
Jacob transformed quadrilateral FGHJ to F'G'H'J'.
Rudik [331]

Answer:

A. Reflection across the line x = 1

Step-by-step explanation:  

Please find the attachment.

We have been given that Jacob transformed quadrilateral FGHJ to F'G'H'J'.  We are asked to find which transformation Jacob used to reflect FGHJ to F'G'H'J'.

Since we know that while reflecting a figure, the line of reflection will lie between the original figure and reflected figure. Each point of the reflected figure will have the same distance from the line of reflection as the corresponding point of the original figure.              

Now let us see our given choices one by one.

A. Reflection across the line x = 1.

Upon looking at point G and G' we can see that both points are equidistant (2 units) from the line x=1. Other corresponding points of both quadrilaterals are also equidistant from line x=1, therefore, Jacob used the reflection across the line x=1 to transform quadrilateral FGHJ to F'G'H'J'.

B. Reflection across the line y = 1 .      

If Jacob had reflected quadrilateral across line y=1, the points of quadrilateral F'G'H'J' will lie in second and third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option B is not a correct choice.

C. Reflection across the line y-axis.

If Jacob had reflected quadrilateral across y-axis, the coordinates of points of quadrilateral F'G'H'J' will be G'(1,4), H'(1,2), J'(4,0) and F'(2,5). Therefore, option B is not a correct choice.

D.  Reflection across the x -axis.

If Jacob had reflected quadrilateral across x-axis, the points of quadrilateral F'G'H'J' will lie in third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option D is not a correct choice.

3 0
3 years ago
ANSWER ALL QUESTIONS PLZ:
kati45 [8]
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8 0
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Read 2 more answers
Solve the equation 2x^{2}+9x-1=x to the nearest 10th
Scilla [17]

Answer:

2x2+9x−1=x

Step 1: Subtract x from both sides.

2x2+9x−1−x=x−x

2x2+8x−1=0

Step 2: Use quadratic formula with a=2, b=8, c=-1.

x=

−b±√b2−4ac

2a

x=

−(8)±√(8)2−4(2)(−1)

2(2)

x=

−8±√72

4

x=−2+

3

2

√2 or x=−2+

−3

2

√2

Step-by-step explanation:

This is what I got but I'm not 100% positive. I checked it on a calculator and it seemed to check out.

4 0
3 years ago
A bag contains 10 black marbles and 6 red marbles. If a red
bonufazy [111]

Answer:

66.67% probability of selecting a black marble from the bag.

Step-by-step explanation:

Initially there are 16 marbles, 10 of which are black and 6 of which are red.

A red marble is drawn and not put back. So now there are 15 marbles, of which 10 are black.

So there is a 10/15 = 2/3 = 0.666% 7 = 66.67% probability of selecting a black marble from the bag.

7 0
3 years ago
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