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Umnica [9.8K]
2 years ago
8

On Monday, Ken spent half of his money on a new game. The next doy he earned $ 12 mowing lawns He now has $32. How much money di

d Ken hoy before bought the game ?
Mathematics
2 answers:
Nikolay [14]2 years ago
8 0

Answer: 40$

Step-by-step explanation: before the mowing 20$ if half is on the game before game would be 40

Kay [80]2 years ago
4 0

Answer:

He had $ 40 before bought the game.

Step-by-step explanation:

Let x be the original amount ( in dollars ) contained by Ken,

His spending on game = half of his money = \frac{x}{2}

So, the remaining money = x-\frac{x}{2} = \frac{x}{2}

Now, his earning = $ 12,

Thus, final amount he has = remaining amount + earning

\frac{x}{2}+12

According to the question,

\frac{x}{2}+12=32

\frac{x}{12}=20

\implies x= 40

Hence, he had $ 40 before bought the game .

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I need help please.
sweet-ann [11.9K]

Answer:

<u>Third Option</u>: y = \frac{5}{4}x

Step-by-step explanation:

Given the points on the graph, (4, 5) and (-4, -5):

In order to determine the equation of the given graph in slope-intercept form, y = mx + b:

Use the given points to solve for the slope:

Let (x₁, y₁) = (-4, -5)

(x₂, y₂) = (4, 5)

m = (y₂ - y₁)/(x₂ - x₁)

m = \frac{5 - (5)}{4 - (-4)}  = \frac{5 + 5}{4 + 4}  = \frac{10}{8} = \frac{5}{4}

Therefore, the slope of the line is: m = \frac{5}{4}.

Next, use one of the given points on the graph, (4, 5) to solve for the y-intercept, b:

y = mx + b

5 = \frac{5}{4} (4) + b

5 = 5 + b

5 - 5 = 5 - 5 + b

0 = b

Therefore, the linear equation in slope-intercept form is: y = \frac{5}{4}x.  The correct answer is Option 3.

8 0
2 years ago
Three numbers that multiply to get to 24
mojhsa [17]

Answer: 1 x 24, 2 x 12, 3 x 8, and 4 x 6.

Step-by-step explanation: The factor pairs of 24 are: 1 x 24, 2 x 12, 3 x 8, and 4 x 6.

                                     Hope This Helps

3 0
3 years ago
Read 2 more answers
Lynne was making cookies and she
charle [14.2K]

Answer:

4 cups of flour

Step-by-step explanation:

We just need to double 2. The phrase "double" means to multiply by 2 so the answer is 2 * 2 = 4 cups of flour.

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3 years ago
Find the x-coordinate of Q' after Q(-2. 5) was reflected over the line y = -x + 4.
Alina [70]
Oh hello thereeeeeeee
3 0
2 years ago
In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

5 0
3 years ago
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