just count by 60's until you get close to 852 and each 60 is 1 bracelet
Given
two angles (150° and 12°) and the shortest side (12 cm) of a triangle
Find
the second-shortest side
Solution
Strategy: Make use of the Law of Sines to find missing side lengths when angles are known. To find the third angle, make use of the sum of angles of a triangle.
The sum of angles of a triangle is 180°, so we have
... 150° + 12° + C = 180°
... C = 180° - 162° = 18°
The law of sines tells us
... c/sin(C) = b/sin(B)
... c = sin(C)·b/sin(B) = sin(18°)·(10 cm)/sin(12°)
... c ≈ 14.9 cm
_____
We are calling the sides a, b, c. We are calling the angles opposite those sides A, B, and C.
Answer: Are you ok?
Step-by-step explanation:
Answer:
This is the answer of this question. Hope it helps.
Answer:
see explanation
Step-by-step explanation:
Since lines a and b are parallel, then
∠NMP and ∠MPQ are same side interior angles and are supplementary, thus
a + a - 20 = 180
2a - 20 = 180 ( add 20 to both sides )
2a = 200 ( divide both sides by 2 )
a = 100, hence
∠NMP = a = 100° and
∠MPQ = a - 20 = 100 - 20 = 80°