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Komok [63]
3 years ago
10

Which systems of equations intersect at point A in this graph?

Mathematics
1 answer:
Svet_ta [14]3 years ago
6 0

Y = 4 x - 9

y = - 3 x - 5

I hope this will help you

i looked this up and this is what i got

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Solve the equation: x+33=40
11Alexandr11 [23.1K]
The answer would be 7. Another way to think of it is subtract 40-33. That gets you 7.
6 0
3 years ago
Draw a visual model to solve 3/8 × 8/11​
dimulka [17.4K]

Answer:

Step-by-step explanation:

(3/8)*(8/11)=(3*8)/(8*11)= 24/88=12/44=6/22=3/11

or you can symplify 8 and get 3/11 right away.

3 0
3 years ago
Gimme the radius circumference and area<br> plsss i beg
Gala2k [10]

Answer:

radius = 5.75 units

circumference = 36.11 units

Area = 103.81625 square units

Step-by-step explanation:

Radius = 11.5 / 2 = 5.75

Circumference = 11.5 x 3.14 = 36.11

Area = 5.75 x 5.75 x 3.14 =

33.0625 x 3.14 =

103.81625 units square

This is all if pi = 3.14

Hope that helps!

4 0
3 years ago
−1 + 6 = 5 + 8 + 4<br> Group of answer choices
Stella [2.4K]

Step-by-step explanation:

your answer is 22.

if you have -1 + 6 = 5 theres your first answer 5

5 + 8 is equal to 13

13 + 5 + 4 = 22

<h3 /><h3>your answer would be a total of 22</h3>

7 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.


Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
7 0
3 years ago
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