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Elanso [62]
2 years ago
10

Write an expression for the operation described below. multiply 6 by u

Mathematics
2 answers:
Masteriza [31]2 years ago
4 0

Answer:

6u

Step-by-step explanation:

it is the algebraic answer.

hope this helps!

Damm [24]2 years ago
3 0

Answer:

the answer is 6×u

Step-by-step explanation:

by and multiply are multiplication

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3 years ago
Simplify by combining like terms. <br> 12+5t−4+15t+1
quester [9]

Answer:

9+20t

Step-by-step explanation:

Look at the terms and see which has t and which is a number when you see like terms, add them or subtract them together to get like terms.

5 0
3 years ago
Which of the following are techniques you have learned so far for solving a quadratic equation?
Usimov [2.4K]
On plato it is A AND B.

6 0
3 years ago
Hey can you please help me posted picture of question
jenyasd209 [6]

The equation of parabola is x=ay^2. If a is positive and y^2 is always greater than zero or equal to zero, then x is also greater or equal to zero. This means that parabola is determined for non-negative x and for all real y.

Tha canonical equation of parabola is y^2=2px, where p>0. The branches of this parabola go up in positive y-direction. When you change x to y and y to x, then the branches of parabola go in positive x-direction, that is right.

Answer: correct choice is A.

6 0
3 years ago
A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
3 years ago
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