Find the slope of a line that goes through point A(8,-4) and C(2, -1)

Sati [7]

Answer:

x = 30

Step-by-step explanation:

$\frac{x}{6} +1=6\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\frac{x}{6}+1-1=6-1\\\\Simplify\\\frac{x}{6}=5\\\\\mathrm{Multiply\:both\:sides\:by\:}6\\\frac{6x}{6}=5\times\:6\\\\Simplify\\x=30$

7 0

3 years ago

The question is in the picture btw

Naddik [55]

Answer:

The width of the andre is 5×5×5=15

Then surface area will be length ×width=15×10=50

4 0

2 years ago

A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$