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3 years ago

Two angles of a triangle measure 57 and 46. What is the measure of the largest exterior angle of the triangle?

Mathematics

1 answer:

irina [24]3 years ago

5 0

Answer:

A. 103°

Step-by-step explanation:

57° + 46° =103°

This shows that the third angle in the triangle is 180°-103°=77°

Therefore the largest exterior angle is 180°-77°=103°

You might be interested in

He is paid a commission of 9 percent of his first $6,000 in sales during the month and 14 percent on all sales over $6,000. What

Agata [3.3K]

Answer:

$1,956.80

Step-by-step explanation:

For amounts over $6000, the commission can be computed as ...

0.14s -300 . . . . . . for sales (s) ≥ 6000

So, for $16,120 in sales, the commission is ...

0.14×$16,120 -300 = $2,256.80 -300 = $1,956.80

The commission schedule suggests that for larger amounts, you divide the problem into two parts: calculate the commission on $6000, and separately calculate the commission on the amount over $6000.

0.14(s -6000) + 0.09(6000)

= 0.14s - 0.14·6000 +0.09·6000

= 0.14s -300 . . . . the formula used above for s ≥ 6000

6 0

3 years ago

The measure of the second angle of a triangle is twice as large as the measure of the first measure of the third angle is 30° le

Alex777 [14]

Applying the triangle sum theorem, we have:

First angle measure = 35°

Second angle = 70°

Third angle = 75°

<h3>What is the Triangle Sum Theorem?</h3>

According to the triangle sum theorem, all angles in a triangle will give a sum of 180 degrees.

First angle measure = x

Second angle = 2x

Third angle = (2x + x) - 30 = 3x - 30

x + 2x + 3x - 30 = 180 [triangle sum theorem]

6x - 30 = 180

6x = 180 + 30

6x = 210

x = 210/6

x = 35

First angle measure = x = 35°

Second angle = 2x = 2(35) = 70°

Third angle = 3x - 30 = 3(35) - 30 = 75°

Learn more about the triangle sum theorem on:

brainly.com/question/7696843

#SPJ1

4 0

2 years ago

If f(x) and g(x) are quadratic functions but (f + g)(x) produces the graph below, which statement must be true?

aksik [14]

Answer:

The leading coefficients of f(x) and g(x) are opposites.

4 0

3 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}$

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

$\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}
\\\\\\
\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
\\\\\\
\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}$

4 0

3 years ago

In a collection of nickels, dimes, and quarters worth $6.90, the ratio of the number of nickels to dimes is 3:8. The ratio of th

dimulka [17.4K]

N=number of nickels
d=number of dimes
q=number of quarters

example
if n:d=3:8
lets say n=3 and d=8
3*8=8*3
so
8n=3d
slightly confusing but go with it, it migh make sense or it might not

n:d=3:8
8n=3d

d:q=4:5
5d=4q

solve for one of them
solve for nickels in first and quarters in second

8n=3d, n=(3/8)d
5d=4q, (4/5)d=q

5n+10d+25q=690
divide by 5 to make it easeir
n+2d+4q=138
sub (3/8)d for n
sub (4/5)d for q
(3/8)d+2d+5(5/4)d=138
(3/8)d+2d+25/4d=138

3/8+2+25/4=
3/8+16/2+50/8=
69/8

(69/8)d=138
times both sides by 8
69d=1104
divide both sides by 69
d=16

16 dimes
sub back

(5/4)d=q
(5/4)16=q
80/4=q
20=q

(3/8)d=n
(3/8)16=n
48/8=n
6=n

6 nickles
16 dimes
20 quarters
yah

8 0

3 years ago