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2 years ago

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Mathematics

1 answer:

Vesna [10]2 years ago

4 0

I don’t really understand this question can you go more into detail

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Find the angle θ between u = <7, –2> and v = <–1, 2>.

Dmitry_Shevchenko [17]

The angle between two vectors is:

CosФ = u - v / Magnitude(u) x magnitude(v)

Magnitude of u = SQRT(7^2 + -2^2) = SQRT(49 +4) = SQRT(53)

Magnitude of v = SQRT(-1^2 +2^2) = SQRT(1 +4) = SQRT(5)

u x v = (7 x -1) + (-2 x 2) = -7 + -4 = -11

cosФ = -11 / sqrt(53) x sqrt(5)

cosФ = -11sqrt265) / 265

Ф =cos^-1(-11sqrt265) / 265)

Ф=132.51 degrees.

7 0

3 years ago

Read 2 more answers

Please help !! Will mark brainliest answer

Norma-Jean [14]

Answer:

x = 12

Step-by-step explanation:

18:24 (comparing the same sides for the similar shapes; 18 and 24) when simplified down is equal to 3:4.

Using this 3:4 scale factor we can find the missing side x.

Solving for x :

$\frac{3}{4}$ × 16 = 12

x = 12

OR: Set up a proportion:

$\frac{24}{16}$ × $\frac{18}{x}$

<em>cross-multiply</em>

16 × 18 = 288

24 × x = 24x

288 = 24x

x = 12

3 0

3 years ago

Adam celebrated his eighteenth birthday with friends at a Chinese restaurant. The bill came to $287.69 without tax. The service

blsea [12.9K]

To find the percent. A trick I learned in middle school was Dr. P

To turn a decimal to a percent and a percent to decimal... (look at picture)

Using that trick...

All you do is multiply $287.69 by .20

Which gives you $57.538 so you can round to either...

$57.54
Or
$57.50
Or
$58

And one of those are your answer!

5 0

3 years ago

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w

Arte-miy333 [17]

Let $k$ be an integer. Suppose there is a triangle with legs of length 16 and $2k+1$ . Then by the Pythagorean theorem, the length of the hypotenuse should be

$\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}$

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if $x=16$ and $y=2k+1$ are integers, then so are $x^2-y^2$ , $2xy$ , and $x^2+y^2$ .

However, $4k^2+4k+257$ is not a perfect square trinomial, which means for any integer $k$ , the length of the hypotenuse is not an integer, so such a triangle doesn't exist.

4 0

2 years ago

If m∠A = m∠B and m∠A + m∠C = m∠D, then<br> m∠B + m∠C = m∠D.

just olya [345]

Answer:

True. The statement is also equivalent to: If m<B + m<C does not equal m<D, then m<A does not equal m<B and m<A + m<C is not equal to m<D.

8 0

2 years ago