Answer:
Step-by-step explanation:
All the triangle's angles measure adds up to a total of 180º
There is an infinite number of values that are in both the domain and range.
Determine the area of the parallelogram with vertices (4, 6, 2), (4, 7, 2), (9, 7, 2), and (9, 8, 2). Use the square root symbol
astra-53 [7]
Answer:
5 square units
Step-by-step explanation:
The parallelogram lies entirely in the plane z=2, so we can treat this as a 2-dimensional problem.
In the order given, the vertices do not define a parallelogram. Two of the sides are parallel, but the other two sides cross each other, for a net area of zero.
If we swap the order of the last two vertices, we get a parallelogram that has a base of 1 unit and a height of 5 units. Its area is ...
A = bh = 1·5 = 5 . . . square units
Answer:sx−3x+1
Step-by-step explanation:
Answer:
Step-by-step explanation:
6) taking 45 degrees as the reference angle,
the adjacent side is √6
The opposite side is x
The hypotenuse is y
Therefore, we would apply trigonometric ratio.
Tan # = opposite side / adjacent side
Tan 45 = x/√6
1 = x/√6
x = 1 × √6 = √6
Cos # = adjacent side/hypotenuse
Cos 45 = √6/y
Cos 45 expressed in surd form is √2/2. Therefore,
√2/2 = √6/y
y √2 = 2√6
y = (2√6)/√2