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Masja [62]
3 years ago
5

Work out 65% of 300.

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0

Answer:

195

Step-by-step explanation:

65%=65÷100=0.65

0.65×300=195

Leto [7]3 years ago
3 0

Step-by-step explanation:

21.6%

mark as brainliest

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Nuetrik [128]

Answer:

IJ is going to be 5400.

Step-by-step explanation:

60*90= 5400.

90 is the right angle on J.

I is 60 degrees.

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2 years ago
I need help solving these problems please.
ddd [48]

5. 15 x 3/4 = 11.25

6. 10 x 1/2 = 5

7.  11 x 2 = 22

8. 12/1.5 = 8

5 0
3 years ago
Becky bought a magazine for $3.68, and the sales tax was 8.25%. How much sales tax did Becky pay on the magazine?
Lerok [7]

Answer:

$0.30

Step-by-step explanation:

3.68*.0825= .3036

3 0
2 years ago
PLEASE SHOW FULL SOLUTIONS!!! WILL MARK BRAINLIEST FOR BEST ANSWER!!
Lubov Fominskaja [6]

Answer:

  • The first option: $265.05

Step-by-step explanation:

<h3>Option 1</h3>

<u>Payment as sequence:</u>

  • 11.75, 12.10, 12.45, ...

<u>This is an AP with:</u>

  • The first term a = 11.75
  • Common difference d = 0.35
  • Number of terms n = 18

<u>Find the sum of the first 18 terms:</u>

  • S₁₈ = (a + a₁₈)*18/2 = (a + a + 17d)*9 = (11.75*2 + 17*0.35)*9  = $265.05
<h3>Option 2</h3>

Flat rate $14.50 per hour

<u>The sum is:</u>

  • $14.50*18 = $261.00

<u>Compared, we see the first option pays more:</u>

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5 0
2 years ago
a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th
hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

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2 years ago
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