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alukav5142 [94]
3 years ago
6

I need help please please

Mathematics
1 answer:
algol [13]3 years ago
5 0

Answer:

its 2/5

Step-by-step explanation:

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What is the solution of -(x + 1) - 5 > 10
Pie
<span> -(x + 1) - 5 > 10
 -x - 1 - 5 > 10
 - x - 6 > 10
Add 6 to the both sides, 
-x - 6 + 6 > 10 + 6
-x > 16
x < -16  [ changed sign 'cause changed -sign ]

In short, Your Answer would be x < -16

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6 0
3 years ago
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If x2 = 20, what is the value of x?
ArbitrLikvidat [17]
The correct answer is the second option: plus or minus square root of 20
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Write the following inequality in slope-intercept form. −6x + 2y ≤ 42
zubka84 [21]
Add the 6x to both sides. Then divide both sides by 2 to get y by itself.

y <= 6x + 42

Note: if it were a -2y, you’d have to flip the inequality sign when dividing by that negative 2.

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Find two numbers the quotient between. Then estimate the quotient. 41÷3
AleksandrR [38]

Answer:

The quotient is between 10 and 15, and the exact answer is 13 with the remainder of 2: 13R2.

Step-by-step explanation:

41 ÷ 3 is a very long answer so do 39 ÷ 3 which equals 13 and since you can't divide 2 by three without negatives, just do it as a remainder of 2, or R2, which means the answer is 13 with the remainder of 2, or just 13R2.

5 0
2 years ago
Applications 24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting h
SVEN [57.7K]

The given function is

h(x)=-16x^2+300x+20

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.

Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

h=-\frac{b}{2a}

Where a = -16 and b = 300.

\begin{gathered} h=-\frac{300}{2(-16)}=\frac{300}{32}=\frac{150}{16}=\frac{75}{8} \\ h=9.375 \end{gathered}

Then, we find k by evaluating the function

\begin{gathered} k=-16(9.375)^2+300(9.375)+20 \\ k=-1406.25+2812.5+20=1426.25 \end{gathered}

Hence, the maximum height is 1426.25 feet.

At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

t=2\cdot9.375=18.75

Hence, the rocket hits the ground after 18.75 seconds.

6 0
1 year ago
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