How are finance charges calculated?

The line y = kx + 6 is a tangent to the graph of

Wittaler [7]

Answer:

Step-by-step explanation:

For equating the equations, you get

x2 + kx - 3x + 4 = 0 eq1

Setting the derivative of f(x) equal to 3 yields

f'(x) = 3

2x + k = 3 eq2

Now we substitute the value of k from eq2 into eq1.

x2 + x(3 - 2x) - 3x + 4 = 0

Solve for x from this equation. Then plug in the value of x into eq2 to solve for k

6 0

3 years ago

SOMEONE HELP ME REALLY FAST !!!!

nadezda [96]

Answer:

just draw the same rectangle as on the left on the right

Step-by-step explanation:

but when finding area instead of unitsx2 use unitsx4

6 0

3 years ago

Can you please help me with these two problems. I've been struggling on this topic for a while now!

Nadya [2.5K]

<u>First Question:</u>

To find the value of K when F is 5 you must plug in 5 for F and solve for K:

5 = $\frac{9}{5}$ k - 455.67

To do this first add 455.67 to both sides (what you do on one side you must do to the other). Since 455.67 is being subtracted on the right side of the equation, addition (the opposite of subtraction) will cancel it out (make it zero) from the right side and bring it over to the left side.

5 + 455.67= $\frac{9}{5}$ k - 455.67 + 455.67

460.67 = $\frac{9}{5}$ k + 0

460.67 = $\frac{9}{5}$ k

Now we must completely isolate k by removing $\frac{9}{5}$ from the right side of the equation. In order to do this you must multiply both sides of the equation by $\frac{5}{9}$ . This is simply the reciprocal of $\frac{9}{5}$ . Multiplying a fraction by its reciprocal always equals 1

460.67 * $\frac{5}{9}$ = $\frac{9}{5}$ k * $\frac{5}{9}$

$\frac{460.67 * 5}{9} =\frac{9*5}{5*9} k$

$\frac{2303.35}{9} = \frac{45}{45}k$

255.927 = k

k ≈ 255.93

<u>Second Question:</u>

y = - $\frac{1}{4} (x + 8) + 2$

X-intercept is set up like so: (0, y). The x value of the x-intercept will ALWAYS be zero. Knowing this you can already plug in zero for the x-value in the equation given above:

y = - $\frac{1}{4} (0 + 8) + 2$

Now all we need to do is solve for the y-value! To do this you must solve using the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction) REMEMBER: IF NOT APPLICABLE TO THE EQUATION YOU MAY SKIP THAT STEP IN PEMDAS .

y = - $\frac{1}{4} (0 + 8) + 2$

Parentheses...

y = - $\frac{1}{4} (0 + 8) + 2$

0 + 8 <<<In the parentheses so you must solve first

8

so...

y = - $\frac{1}{4} (8) + 2$