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natita [175]
2 years ago
5

1 David buys 4 kg of apples from the supermarket for £1.60.

Mathematics
1 answer:
liberstina [14]2 years ago
4 0

Answer:

£ 2.8

Step-by-step explanation:

4 kg = 1.60

1 kg= 1.6/4 = £0.4

7 kg = 0.4*7 = £2.8

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What is the value of X2/Y1 when x =10 and Y =five?
aleksandrvk [35]

Answer:

Step-by-step explanation:

hello : 10/5=2

8 0
3 years ago
The cube root of 5 times the square root of 5 over the cube root of 5 to the 5th power
Fiesta28 [93]
(cube root of 5)  * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)

This becomes easier if we switch to fractional exponents:


  5^(1/3) * 5^(1/2)         5^(1/3 + 1/2)       5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3)                  5^(5/3)                 5^(5/3) 

Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.

                                                            1
Thus,  5^[5/6 - 5/3] = 5^(-5/6)  =  --------------
                                                        5^(5/6)

That's the correct answer.  But if you want to remove the fractional exponent from the denominator, do this:

    1            5^(1/6)         5^(1/6)
---------- * ------------- = --------------    (ANSWER)
5^(5/6)       5^(1/6)              5
7 0
3 years ago
a train travels 120 miles in 1 1/2 hours. At this rate how many miles will the train travel in 6 hours
Morgarella [4.7K]

Answer:

480 miles

Step-by-step explanation:

120/1.5=80

80*6=480

6 0
3 years ago
Read 2 more answers
If one of the roots of the quadratice quation x2+kx-12=0is4,what is the value of k?
uysha [10]
<h3>Given Equation:</h3>

\huge \purple {\rm { {x}^{2}  + kx - 12 = 0}}

<h3>Value:</h3>

\huge \purple {\rm {x = 4}}

<h3>To Find:</h3>

\huge \purple {\rm {The \: value \: of \: k.}}

<h3>Solution:</h3>

\huge \purple {\rm { {(4)}^{2}  + k(4) - 12 = 0}}

\huge \purple {\rm {or, \: 16 + 4 k - 12 = 0}}

\huge \purple {\rm {or, \: 4k =  - 4}}

\huge \purple {\rm {or, \: k =  \frac{ - 4}{4}  =  - 1}}

<h2>Answer:</h2>

\huge \purple {\sf {The \: value \: of \: k \: is \: -1}}

3 0
3 years ago
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Solving Systems of linear equations by graphing. no graphing device.
valentina_108 [34]

Answer: (1,3)

Step-by-step explanation:

6 0
2 years ago
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