Assume the smaller one is x, then the other ones will be x+2 and x+4
x(x+2) + 2 = 5(x+4)
x^2 + 2x - 5x - 18 = 0
-> x^2 - 3x - 18 = 0
-> (x-6)(x+3) = 0
-> x = 6 or -3, since x must be positive, then x = 6
So the numbers are: 6, 8, 10
<span> y+15.5=|x|
</span><span> y=|x|-15.5 </span>
9/16 + 1/4
9+4/16
13/16
Alternative form
0.8125
I think you are missing part of the problem. If you had another equation or a value for x you could solve it.