Hope this helps sorry if it’s wrong
The reflection line is located at y = -x
For point J, x is -2, so y = -(-2), which equals 2.
When it is a reflection across Y, the X values remain the same.
Find the distance of the Y point to the reflection line,
The distance from -1 to 2 is 3 units.
The new point needs to be the same distance from the reflection line.
2 + 3 units = 5.
Point J' would be (-2,5)
Answer:
Step-by-step explanation:
An x value of 0 can only be plugged into the equation that has a domain that includes 0. The first function's domain is between -2 and -4, so 0 is not included in that domain. In the third function, the domain is between 1 and 3, so 0 is not included in that domain, either. The middle function's domain does include 0 (0 falls between -2 and 1) so we can only evaluate this function at an x value of 0.
g(0) = -0 - 1 so
g(0) = -1
Answer:
c. ![\frac{1}{12n} = {[12n]}^{-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B12n%7D%20%3D%20%7B%5B12n%5D%7D%5E%7B-1%7D)
Step-by-step explanation:
![[\frac{1}{4}][\frac{2}{5}][\frac{1}{2}][\frac{4}{7}][\frac{5}{8}][\frac{2}{3}][\frac{7}{n}] = \frac{560}{6720n} = [12n]^{-1} = \frac{1}{12n}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B4%7D%5D%5B%5Cfrac%7B2%7D%7B5%7D%5D%5B%5Cfrac%7B1%7D%7B2%7D%5D%5B%5Cfrac%7B4%7D%7B7%7D%5D%5B%5Cfrac%7B5%7D%7B8%7D%5D%5B%5Cfrac%7B2%7D%7B3%7D%5D%5B%5Cfrac%7B7%7D%7Bn%7D%5D%20%3D%20%5Cfrac%7B560%7D%7B6720n%7D%20%3D%20%5B12n%5D%5E%7B-1%7D%20%3D%20%5Cfrac%7B1%7D%7B12n%7D)
* To make this simpler, reduce these two fractions in lowest terms.
I am joyous to assist you anytime.
