The given question is a quadratic equation and we can use several methods to get the solutions to this question. The solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

<h3>Quadratic Equation</h3>

Quadratic equation are polynomials with a second degree as it's highest power.

An example of a quadratic equation is

$y = ax^2 + bx + c$

The given quadratic equation is $24x^2 + 2x = 15$

Let's rearrange the equation

$24x^2 + 2x = 15\\24x^2 + 2x - 15 = 0$

This implies that

a = 24
b = 2
c = -15

The equation or formula of quadratic formula is given as

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}$

We can substitute the values into the equation and solve

$y = \frac{-b +- \sqrt{b^2 - 4ac} }{2a}\\y = \frac{-2 +- \sqrt{2^2 -4 * 24 * (-15)} }{2*24} \\y = \frac{-2+-\sqrt{4+1440} }{48} \\y = \frac{-2+-\sqrt{1444} }{48} \\y = \frac{-2+- 38}{48} \\y = \frac{-2+38}{48} \\y = \frac{3}{4}\\ \\or\\y = \frac{-2-38}{48} \\y = \frac{-40}{48} \\y = -\frac{5}{6}$

From the calculations above, the solution to the equation are 3/4 and -5/6 and the greater of the two solutions is 3/4

Learn more on quadratic equation here;

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7 0

1 year ago

Determine whether the triangles are congruent by sss sas asa aas or hl

Blababa [14]

AAS.
The vertical angle.
The marked angle.
And the marked side.

7 0

2 years ago

the volume of cube A is 216 cubic inches. the length of each edge in cube B is 2 inches longer than the length of each edge in c

Aleonysh [2.5K]

If the side lengths of B are 2x as long as the side lengths of A then the volume of B should be the volume of A^2
216^2=46,656
46,656-216=46,440

This can be more easily displayed with smaller numbers

If cube X were 2*2*2 then the volume would be 8
If cube Y were 4*4*4 then the volume would be 64
8(volume of cube X)^2=64(volume of cube Y)

7 0

3 years ago