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Studentka2010 [4]
3 years ago
5

7 - 3x = x - 4(2 + x)​

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0
The answer will be no solution

aleksandrvk [35]3 years ago
7 0

Answer:

the answer is no solution

Step-by-step explanation:

7+−3x=x+(−4)(2)+(−4)(x)(Distribute)

7+−3x=x+−8+−4x

−3x+7=(x+−4x)+(−8)(Combine Like Terms)

−3x+7=−3x+−8

−3x+7=−3x−8

Step 2: Add 3x to both sides.

−3x+7+3x=−3x−8+3x

7=−8

Step 3: Subtract 7 from both sides.

7−7=−8−7

0=−1

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It takes a train 60 seconds to completely drive through a bridge of 1260 m, and 90 seconds to completely drive through a tunnel
Olegator [25]

The length of train is 120 meters

The speed of train is 25 meter per second

<u><em>Solution:</em></u>

The speed is given by formula:

speed = \frac{distance}{time}

Given that,

It takes a train 60 seconds to completely drive through a bridge of 1260 m

And 90 seconds to completely drive through a tunnel of 2010 m

Let the length of the train be "x"

<em><u>The total distance travelled by the train across the bridge is given by:</u></em>

total distance = x + 1260 + x = 2x + 1260

[ here we use x + x to represent that train completely drives through bridge ]

The time taken is given as 60 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 1260}{60}

<em><u>The total distance travelled by the train through the tunnel is given by:</u></em>

total distance = x + 2010 + x = 2x + 2010

The time taken is given as 90 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 2010}{90}

The speed of the train was the same in both cases.

Equate both speeds

\frac{2x+ 1260}{60} = \frac{2x+ 2010}{90}

\frac{x+630}{30} = \frac{x+1005}{45}

45(x+630) = 30(x+1005)\\\\45x + 28350 = 30x + 30150\\\\45x - 30x = 30150 - 28350\\\\15x = 1800\\\\x = 120

Thus length of train is 120 meters

<em><u>Find the speed of train:</u></em>

speed = \frac{2x+ 1260}{60}\\\\speed = \frac{2(120) + 1260)}{60}\\\\speed = 25

Thus speed of train is 25 meter per second

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Answer:

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Step-by-step explanation:

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