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3 years ago

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..

Mathematics

1 answer:

natima [27]3 years ago

3 0

Given:

The point is (-2,4).

To find:

Whether the point (-2,4) satisfy $y$ or $y >3x+5$ .

Solution:

We have a point (-2,4).

Substituting x=-2 in 3x+5 and check whether it is greater, equal or less than y value, i.e., 4.

$3x+5=3(-2)+5$

$=-6+5$

$=-1$

-1 is less than 4.

$3x+5$

In can be written as

$y>3x+5$

Therefore, the given point (-2,4) satisfy $y >3x+5$ .

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NNADVOKAT [17]

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6 0

3 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

Aloiza [94]

The perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners. Kite is quadrilateral, in which. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

The figure is missing.

On a coordinate plane, kite WXYZ is shown (please refer to the picture)

We have a kite and the coordinates of the kite are:

Point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Using the distance formula we can find the distance between coordinates:

$\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between W and X:

$\rm WX=\sqrt{(2+3)^2+(3-3)^2}$

WX = 5 units

Similarly, distance between X and Y:

XY = √53 units

YZ = √53 units

ZW = 5 units

Perimeter = sum of the all sides

Perimeter = 5 + √53 + √53 + 5

Perimeter = (10 + 2√53) units

Thus, the perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Learn more about the quadrilateral here:

brainly.com/question/6321910

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