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3 years ago

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..

Mathematics

1 answer:

natima [27]3 years ago

3 0

Given:

The point is (-2,4).

To find:

Whether the point (-2,4) satisfy $y$ or $y >3x+5$ .

Solution:

We have a point (-2,4).

Substituting x=-2 in 3x+5 and check whether it is greater, equal or less than y value, i.e., 4.

$3x+5=3(-2)+5$

$=-6+5$

$=-1$

-1 is less than 4.

$3x+5$

In can be written as

$y>3x+5$

Therefore, the given point (-2,4) satisfy $y >3x+5$ .

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<u>Solution:</u>

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The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

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Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

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3 years ago

Please help me<br>simplify<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B32%20-%20%20%5Csqrt%7B50%7D%20%7D%20" id="TexFormul

Mnenie [13.5K]

Answer:

$\sqrt{32-5\sqrt{2} }$

Step-by-step explanation: I hope it helps :)

$\sqrt{32-\sqrt{50} } \\\\simplify \: \sqrt{50} \:to \:5\sqrt{2} \\\\= \sqrt{32-5\sqrt{2} } \\\\Decimal Form: 4.992888$

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3 years ago

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..​

.. pls help me....!!!!! Determine whether the point (-2,4) satisfy y<3x+5,y=3x+5 or y >3x+5..