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Goryan [66]
3 years ago
9

Jerry purchased three pens for $1.19 each and six notebooks for $2.29 each. How many did Jerry spend altogether?

Mathematics
1 answer:
Masteriza [31]3 years ago
6 0

Hi!

We will find the sum you are looking for like this:

3 * 1,19$ + 6 * 2,29$ = 3,57$ + 13,74$ = 17,31$.

Hope this helps!

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Umnica [9.8K]
Alrigth and B....

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4 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Need answer fast thx
bagirrra123 [75]

Answer:

thats A daddy-o

Step-by-step explanation:

there are 4 out of 12

1/3

33.3333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333 is 1/3

6 0
3 years ago
Reduce 7y + 2y 2 - 7 by 3 - 4y?
Pepsi [2]

<span><span>(<span>7y+2<span>y2</span>−7</span>)</span>−<span>(<span>3−4y</span>)</span></span>

<span>=<span>7y</span><span>+4y</span>+2<span>y2</span><span>−7</span><span>−3</span></span>

<span>=11y−2<span>y2</span>−<span>10</span></span>

Hope this helps


3 0
3 years ago
Read 2 more answers
What are the removable discontinuities of the following function? f (x) = StartFraction x squared minus 36 Over x cubed minus 36
jeyben [28]

Answer:

the removal discontinuity of the following function at x=-6 or x=6.

Step-by-step explanation:

factoring  f(x)  = (x - 6)(x + 6)

                         ----------------

                          x(x - 6)^x + 6)

3 0
2 years ago
Read 2 more answers
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