NEED HELP NOW...NEED CORRECT ANSWER...WILL MARK BRAINLIEST...

Which statement is correct with respect to f(x) = -3|x − 1| + 12?

CaHeK987 [17]

The answer is D since there a negative 3 it will face down.

5 0

3 years ago

How would you simplify the expression represented by the diagram below?

tangare [24]

A i hope good luck on the test

6 0

3 years ago

How do I translate the product of h and 4 is subtracted from one-fifth of x is 35 to an equation?

kolezko [41]

So we know that the word 'product' means multiplication, and that means that h and 4 are being multiplied. Also, one-fifth of x is another way of saying that one-fifth is being multiplied with x. So then we can construct the equation:

$\frac{1}{5} x-(4*h)=35$

And we can then simplify this by taking out the multiplication sign:

$\frac{1}{5}x-4h=35$

And so since we do not know what x or h is equal to, this is as far as we can go.

8 0

3 years ago

Jean works for the government and was conducting a survey to determine the income levels of a number of different neighborhoods

Brrunno [24]

Answer:

0.0418 = 4.18% probability that the average income level in the neighborhoods was less than $38,000.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .