Answer:
D. ∠E ≅ ∠N
Step-by-step explanation:
The pair of sides meet at vertex E in ∆DEF and at vertex N in ∆MNO. Since the sides that make up angles E and N are shown congruent, it is sufficient to show ...
∠E ≅ ∠N
Then the SAS congruence postulate can be claimed.
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<em>Additional comment</em>
The alternative is to show DF ≅ MO. That would allow you to claim SSS congruence. That is not an answer choice.
Answer:
(-1, -7) (0, -1) (1, 5) (5, 29)
Step-by-step explanation:
okay so the equation is y = 6x - 1
all you have to do is plug in all the x values to get the y
y = 6(-1) - 1
y = - 6 - 1
y = -7
y = 6(0) - 1
y = 0 - 1
y = -1
y = 6(1) - 1
y = 6 - 1
y = 5
y = 6(5) - 1
y = 30 - 1
y = 29
Answer:
The pictures is unclear resend again.
The answer is 24, 26, and 28
Complete Question:
a) Is it plausible that X is normally distributed?
b) For a random sample of 50 such pairs, what is the (approximate) probability that the sample mean courtship time is between 100 min and 125 min?
Answer:
a) It is plausible that X is normally distributed
b) probability that the sample mean courtship time is between 100 min and 125 min is 0.5269
Step-by-step explanation:
a)X denotes the courtship time for the scorpion flies which indicates that is a real - valued random variable, and since normal distribution is a continuous probability distribution for a real valued random variable, it is plausible that X is normally distributed.
b) Probability that the sample mean courtship time is between 100 min and 125 min




From the probability distribution table:

