Problem 1
The largest value would be 1 and the smallest would be
-1.
To get a product of 1, either all are 1 or two of the
variables are -1 and the other one is 1.
Largest value = (1)^2 * (1)^3 * (1)^4 =1
Smallest value = (- 1)^2 * (- 1)^3 * (1)^4 = -1
The difference is:
largest value – smallest value = 1 – (-1) = 2
<span>Therefore the answer is letter D.</span>
Problem 2
% loss = (final price – initial price) * 100%/ initial
price
where, final price per dozen = ( $2.50 / piece) (12 piece
/ dozen) = $30
Therefore,
% loss = ($30 - $33) * 100 / $33
% loss = - 300/ 33 = 9 1/11
<span>Therefore the answer is <span>letter C.</span></span>
First, write an equation for each scenario.
$300 quarterly is equivalent to $1200 a year.
The first equation is y= 2700x.
The second equation is y=2700x.
The answer is both; their deals are the same.
ANSWER
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:

From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;

This simplifies to;


Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
Answer:
y=3/2x-3/2
Step-by-step explanation:
Answer:
If P= price of the hardcover book, then
We have to spend $25-P, if P<$25; or $0 if P>= $25
Step-by-step explanation:
Lets call P the price of the hardcover book, in $. We can suppose that P is less than 25, otherwise we shoudnt spend on anything else to get the free shipping. If X is the amount that we have to spend to reach 25, then we get that P+X = 25. If P is known, we can obtain X by substracting P in both sides, therefore
X = 25-P
We conclude that if the price of the book P is less than 25, then we have to spend $25-P. Otherwise we have to spend 0.