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Sliva [168]
3 years ago
14

Explain why the formula for sample variance is different from the formula for population variance. Why is it inappropriate to us

e the formula for population variance in calculating the variance of a sample
Mathematics
1 answer:
Aliun [14]3 years ago
3 0

Step-by-step explanation:

The difference in the formula of population and sample variance can be explained as:

Population variance is said to be the value of variance that is calculated from population data, whereas sample variance refers to the variance calculated from sample data. This is the reason why value of denominator in the formula for variance in case of sample data is ‘n-1’, while it is ‘n’ for population data. Hence, the result of both variance and standard deviation derived from sample data is larger than those found out from population data.

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What is the slope of a linear function that passes between (2, 7) and (5, 12)?
Grace [21]

The formula of slope,

→ (y2 - y1)/(x2 - x1)

Then the slope will be,

→ m = (12 - 7)/(5 - 2)

→ [ m = 5/3 ]

Hence, thy slope is 5/3.

4 0
1 year ago
PLEASE HELP!!!!! DUE TODAY!!!!!
prisoha [69]

Answer:

12.4 cm³

Step-by-step explanation:

From the picture attached,

Radius of the circular top of the cone = \frac{\text{Diameter}}{2} = \frac{2}{2}=1

Height of the cone = h

Lateral height of the cone = h

By applying Pythagoras theorem in the right triangle of the cone,

l² = r² + h²

6² = 1² + h²

h = \sqrt{36-1}

h = \sqrt{35}

Ice cream needed to fill one cone = Volume of the cone

Since, formula for the volume of the cone V = \frac{1}{3} \pi r^{2} h

V = \frac{1}{3}\pi (1)^2(\sqrt{35})

   = 6.195

   ≈ 6.20 cm³

Ice cream needed to fill the two cones = 2 × 6.20

                                                                 = 12.4 cm³

Therefore, ice cream needed to fill the two cone = 12.4 cm³

4 0
3 years ago
Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

(b)2(89x+84-x^2\pi)

Step-by-step explanation:

The dimensions of the larger rectangular field are:

  • Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

  • Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

8 0
4 years ago
PLEASE HELP ASAP!!!! WILL MARK BRAINLIEST !!!
Veronika [31]
The answer is D. The last one
6 0
4 years ago
-13 =\dfrac r9+8−13= <br> 9<br> r<br> ​ <br> +8
inna [77]

Answer:

Ello, estoy aquí para ayudar, pero hablo español, con suerte, entenderás que lo estoy intentando.

56738w7421098548091672949123749279102

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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