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3 years ago

Lead has a density of 11.3 g/cm3. what is the volume of a 15.1 g block of lead?

1 answer:

Crank3 years ago

8 0

Hey there:

density = 11.3 g/cm³

mass = 15,1 g

Therefore:

D = m / V

11.3 = 15.1 / V

V = 15.1 / 11.3

V = 1.336 cm³

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describe how a pure dry sample of solid lead carbonate can be obtained from sodium carbonate solution and lead nitrate solution

djyliett [7]

Answer:

Soluble salts can be made by reacting acids with soluble or insoluble reactants. Titration must be used if the reactants are soluble. Insoluble salts are made by precipitation reactions.

Making insoluble salts

An insoluble salt can be prepared by reacting two suitable solutions together to form a precipitate.

Determining suitable solutions

All nitrates and all sodium salts are soluble. This means a given precipitate XY can be produced by mixing together solutions of:

X nitrate

sodium Y

For example, to prepare a precipitate of calcium carbonate:

X = calcium and Y = carbonate

mix calcium nitrate solution and sodium carbonate solution together

calcium nitrate + sodium carbonate → sodium nitrate + calcium carbonate

Ca(NO3)2(aq) + Na2CO3(aq) → 2NaNO3(aq) + CaCO3(s)

It also works if potassium carbonate solution or ammonium carbonate solution is used instead of sodium carbonate solution. Remember that all common potassium and ammonium salts are soluble.

please mark as brainliest

Explanation:

7 0

2 years ago

Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2

NemiM [27]

Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

8 0

3 years ago

Ratio of atoms in Hydrochloric acid

Lesechka [4]

One to one ratio

The formula of hydrochloric acid is HCl so there is one atomic of hydrogen and one atom of oxygen

7 0

3 years ago

A 15.0 L rigid container was charged with 0.5 atm of Krypton gas and 1.5 atm of chlorine gas at 350 C. The krypton and chlorine

Angelina_Jolie [31]

The mass of krypton tetrachloride that can be produced assuming 100% yield is mathematically given as

molar mass=33.29g

<h3>What mass of krypton tetrachloride can be produced assuming 100% yield?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Therefore

n=(0.50)(15.)/0.082*623

n=0.147mol

Hence for clorine

n=0.441mol

Given the reaction

Kr+2cl2---->KrCL4

Hence

molar mass=225.60*0.147

molar mass=33.29g