1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aneli [31]
3 years ago
8

Whos the best airbender ever lol

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0

Answer:

HMMMMMM?11!?!?!!>!>?!?  like avatar like water bender or fir bender air bender?????

Step-by-step explanation:

Sholpan [36]3 years ago
5 0

Answer:

me

Step-by-step explanation:

You might be interested in
Some seeds contain fluffy parachute like structure why​
alekssr [168]

lowkeyokfgfggfggeeeeeeeeeeeeeeeeeee

7 0
3 years ago
An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

\Rightarrow p=1-7\times 10^{-6}=0.999993.

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

3 0
3 years ago
One more than three times a number is less than the number decreased by five. solve and graph
Genrish500 [490]
Whats the graph ??
 i need it to find the answer


4 0
3 years ago
What is the value of x?
Helga [31]

2x+20=3x-30

x=50

2x+20=3x-30

x=50

2x+20=3x-30

x=50

2x+20=3x-30

x=50

7 0
3 years ago
What is the value of the expression 0.52?
polet [3.4K]

Answer:

0.25

Step-by-step explanation:

lets say you have half a cake

multiplying a decimal is the same as multiplying its counterpart

basically, you divide half a cake in half

0.25 of a cake, or 1/4

uwu

6 0
3 years ago
Read 2 more answers
Other questions:
  • Write (1/6) to the 3rd power as a product of the same factor.then find the value
    12·1 answer
  • What is the value of x?
    12·2 answers
  • Work out 25% of 30 meters?
    5·2 answers
  • 8.97x6.8 i need you to solve this and show your work as well pales help
    12·2 answers
  • Which number is between pi and the square root of 14
    12·1 answer
  • M^1/3 divided by m^1/5
    11·1 answer
  • Choose the equation that represents a line that passes through points (-3, 2) and (2, 1).
    7·1 answer
  • Can anyone help me, I think we need to use desmos
    9·1 answer
  • What value of x makes this equation true? HELP ASAP PLZ PLZ PLZ PLZ
    14·2 answers
  • Caroline think of a number add 9 then divide by 6 gets the answer 10
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!