The answer is e, as in terms of d, proteins are not sandwiched between the two bilayers, but wedged in the bilayer to selectively let in different molecules. With c, phospholipids do not drift, into the membrane, for it is the membrane itself. With b it is the other way around, the phospholipid bilayer makes up the membrane, and proteins are embedded into it. Lastly, for a, a fluid mosaic model wouldn’t portray phospholipids drifting in the dark phospholipid bilayer, as they are an independent molecule consisting only as the cell membrane. Hope that’s helpful! :)
Answer:
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Explanation:
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Answer:
The solubility of any substance in water depends on its polarity. The polar molecule dissolves more easily in the water than the non polar molecule. Amino acids have different polarity at different pH.
(a) (Lys-Ala)3 : The (Lys-Ala)3 contain more positive charge and highly polar the at pH 7 as compared with the (Gly)20 that remains uncharged and has less polarity.
(b) (Glu)20 :This amino acids negatively charged at pH 7 and highly polar than the (Phe-Met)3 which is non polar or less polar and hence least soluble in water.
(c) (Asn-Ser-His)5 is highly polar at pH 3 as compared with the (Ala-Asp-Gly)5 that contains the carboxylate groups of Asp residues that are partially neutral. The (Asn-Ser-His)5 contains = the imidazole groups of His residues are fully polar and soluble in water.
(d) (Asn-Ser-His)5 is polar at pH 6.0 because both have polar side chains Ser but (Asn-Ser-His)5 is only partially partially protonated due to the His side chains. Thus, (Asn-Ser-His)5 is more soluble in water.
<span>biomes vary in their rates of net primary production-biomass that remains after cellular respiration limited by sunlight and nutrients available
In general, warmer and wetter biomes have higher net primary productivity than colder and drier biomes. The reason for this trend is that plants require sunlight, water, and temperatures warm enough to grow. This is true even in aquatic ecosystems, where sunlight and the availability of nutrients determine the level of net primary productivity.</span>
Answer:
How bright the star appears at a standard distance of 32.6 light years or 10 parsecs.
Explanation:
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