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marysya [2.9K]
3 years ago
15

Whats the Diameter? I really need help understanding this

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0

Answer:

1.8 in

Step-by-step explanation:

we know the equation for the volume of a cone is pi*r^2 h/3=3.6

pi r^2 *4.2=10.8

solve for r

r is about 0.9 so diameter is 1.8 in

Arada [10]3 years ago
3 0

Answer:

1.8 in.

Step-by-step explanation:

Hi there!

<u>1) Determine the radius of the base</u>

V=\frac{1}{3} \pi r^2h where r is the radius of the base and h is the height of the cone

Plug in the known values (h=4.2, V=3.6)

3.6=\frac{1}{3} \pi r^2(4.2)

Isolate r; divide both sides by 4.2

\frac{3.6}{4.2} =\frac{1}{3} \pi r^2\\\frac{6}{7} =\frac{1}{3} \pi r^2

Multiply both sides by 3

\frac{6}{7}*3 =\pi r^2\\\frac{18}{7}=\pi r^2

Divide both sides by π

\frac{18}{7\pi }=r^2

Take the square root of both sides

\sqrt{\frac{18}{7\pi }} =r

<u>2) Determine the diameter</u>

Now that we have the radius, to find the diameter, multiply r by 2:

d=\sqrt{\frac{18}{7\pi }}*2\\d=1.8

Therefore, the diameter is 1.8 in. when rounded to the nearest tenth.

I hope this helps!

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<em>use </em><em>the </em><em>formula</em><em> for</em><em> </em><em>the</em><em> </em><em>nth </em><em>term </em><em>of </em><em>an </em><em>ap </em><em>Tn=</em><em>a+</em><em>(</em><em>n-1)</em><em>d</em>

<em>T12=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>T18=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em>therefore</em><em> </em><em>come </em><em>up </em><em>with </em><em>two </em><em>equations</em>

<em>T12=</em><em>a+</em><em>(</em><em>1</em><em>2</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>0</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>1</em><em>d</em><em>(</em><em>1</em><em>s</em><em>t</em><em> </em><em>equation</em><em>)</em>

<em>T18</em><em>=</em><em>a+</em><em>(</em><em>1</em><em>8</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>3</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>7</em><em>d</em><em>(</em><em>2</em><em>n</em><em>d</em><em> </em><em>equation</em><em>)</em>

<em>then </em><em>solve </em><em>both </em><em>as </em><em>a </em><em>simultaneous</em><em> </em><em>equation</em>

<em>a+</em><em>1</em><em>1</em><em>d</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>1</em><em>7</em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>5</em>

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<em>use </em><em>one </em><em>of</em><em> the</em><em> </em><em>equations</em><em> </em><em>to </em><em>find </em><em>the </em><em>first</em><em> </em><em>term</em>

<em>a+</em><em>1</em><em>1</em><em>(</em><em>0</em><em>.</em><em>5</em><em>)</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>5</em><em>.</em><em>5</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>-</em><em>5</em><em>.</em><em>5</em>

<em>a=</em><em>5</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

<em>please </em><em>mark</em><em> </em><em>as </em><em>brainliest</em>

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