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3 years ago

11

Look at the pic plsssssss

1 answer:

Deffense [45]3 years ago

5 0

Answer:

I can't see it

Step-by-step explanation:

you should zoom in a little bit please

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Landscaping company A charges a $50 fee plus $18 an hour and landscaping company B charges $20 per hour and a fee of $30. At how

Inessa05 [86]

$\text{Hello there!}\\\\\text{In this question, we're trying to find when both companies cost the same}\\\\\text{We know that landscaping company A charges \$50 fee plus \$18 an hour}\\\\\text{That would be represented as:}\,\,y=18x+50\\\\\text{We know that landscaping company B charges \$20 per hour and a \$30 fee}\\\\\text{That would be represented as:}\,\,y=20x+30\\\\\text{We would get both equations, put them together, and solve}\\\\18x+50=20x+30\\\\\text{Solve:}\\\\18x+50=20x+30\\$

$\text{Subtract both sides by -20x}\\\\-2x+50=+30\\\\\text{Subtract both sides by 50}\\\\-2x=-20\\\\\text{Divide by -2}\\\\\large\boxed{x=10}\\\\\text{They're the same price at 10 hours}\\\\\text{I hope this helps!}\\\text{Best regards,}\\\text{MasterInvestor}$

3 0

3 years ago

Andrew [12]

Answer:

$8.80

Step-by-step explanation:

10% of 8 is .80 so 80 cents. 80 cents plus the 8 dollars leaves Jamie paying $8.80 at the end of the day.

3 0

3 years ago

It’s a picture it kinda looks like text but it’s a pic

Taya2010 [7]

Answer:

its d

Step-by-step explanation:

2.1 ÷ 4 = .525

.525 - .2 = .325

round .325 to .33

8 0

3 years ago

Read 2 more answers

Find the volume of the region between the cylinder z=3y^2 and the xy-plane that is bounded by the planes x=0,x=1 ,y=-1 and . z =

son4ous [18]

Answer:

The volume of the region V = 2

Step-by-step explanation:

Given that:

$z_1 = 3y^2$ ;

where initially;

$z_o = 0; \ x_o = 0; \ x_1 = 1; \ y_o= -1; \ y_1 = 1$

The volume of the region is given by a triple which is expressed as:

$V = \int_x \int_y \int_z \ dz \ dy \ dx$

$V = \int \limits ^{x_1 = 1}_{x_o=0} \int \limits ^{y_1 = 1}_{y_o=-1} \int \limits ^{z_1 = 3y^2}_{z_o=0} \ dz \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \int \limits ^{3y^2}_{0} \ dz \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \Bigg [z \Bigg]^{3y^2}_{0} \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \Bigg [3y^2 \Bigg] \ dy \ dx$

$V = \int \limits ^{1}_{0} \Bigg [\dfrac{3y^3}{3} \Bigg]^1_{-1} \ dx$

$V = \int \limits ^{1}_{0} \Bigg [\dfrac{3(1)^3}{3}- \dfrac{3(-1)^3}{3} \Bigg] \ dx$

$V = \int \limits ^{1}_{0} \Bigg [1-(-1)\Bigg] \ dx$

$V =2 \Bigg [x \Bigg] ^1_0$

V = 2

Thus, the volume of the region is 2

3 0

3 years ago

a business-owners open one store in town a the equationrepresents the anticipated profit after T years

Harman [31]

Answer

I'm quite confused on what it is you're asking.

Do you want me to create an equation for you?

Step-by-step explanation:

6 0

3 years ago